2Fe(OH)3 = Fe2O3 + 3H2O
Fe2O3 +6HCl = 2FeCl3 +3H2O
2FeCl3 = 2FeCl2 + Cl2
FeCl2 + 2NaOH = Fe(OH)2 + 2NaCl
400г 15% x
Na2CO3+2HCl=2NaCl+H2O+CO2
106г/моль 22.4
100-15%=85%= 0.85
м(Na2CO3)=0.85*400=340 г
340 ---- х
106 ----- 22.4 х=71.8
<span>FeCl2 + 2 KOH </span>→<span> Fe(OH)2 + 2 KCl
</span><span>AgNO3 + KCl </span>→<span> AgCl + KNO<span>3
</span></span><span>Zn(NO3)2 + 2 NaOH </span>→<span> 2 NaNO3 + Zn(OH)<span>2
</span></span><span>BaCO3 </span>→<span> BaO + CO<span>2
</span></span>Fe + CuCl2 → Cu + FeCl2
<span>Na2SiO3 + 2HCl → SiO2 + 2NaCl + H2O</span>
A.4 Б.2 B.5 Г.6 .............................................................................