<span>Раствор: BаСІ2 =Bа2+ + 2СІ- </span>
<span>К(-) Bа2+, Н2О 2Н2О+ 2е =Н2 + 2ОН- </span>
<span>А(+) 2СІ- 2СІ- -2е=СІ2 </span>
<span>BаСІ2 +2Н2О=Bа(ОН)2 + Н2 + СІ2</span>
Н2SO4+Na2SO3=Na2SO4+SO2+H2O
Н2SO4+Ba(NO3)2=BaSO4+2HNO3
HNO3+KOH=KNO3+H2O
СH4 + Cl2 ----> CH3Cl + HCl
<span>2CH3Cl + 2Na -----> 2NaCl + CH3-CH3 </span>
<span>CH3-CH3 + Cl2 ----> CH3-CH2Cl + HCl </span>
<span>2CH3-CH2Cl + 2Na ----> 2NaCl + CH3-CH2-CH2-CH3 </span>