Это если все таки 5 вещ-во - бутан (C4H10)
2RCOOH+Mg=(RCOO)2Mg+H2↑;
V=224 мл=0,224 л;
1,48 г RCOOH ---0,224 л H2;
x г RCOOH ----22,4 л H2;
x=22,4*1,48/0,224=148;
2n=148;
n=148/2=74;
CH3CH2COOH
Первое:
<span><span>2</span><span>Na</span><span>O</span><span>H</span></span><span> + </span><span><span>H</span><span>2</span><span>S</span><span>O</span><span>4</span></span><span> = </span><span>Na</span><span>2</span><span>S</span><span>O</span><span>4</span><span> + </span><span>2</span><span>H</span><span>2</span><span>O</span>
<span><span>2</span><span>Na</span>+<span> + </span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> = </span><span>2</span><span>Na</span>+<span> + </span><span>S</span><span>O</span><span>4</span>2−<span> + </span><span>2</span><span>H</span><span>2</span><span>O</span></span>
<span><span><span>2</span><span>O</span><span>H</span>−<span> + </span><span>2</span><span>H</span>+<span> = </span><span>2</span><span>H</span><span>2</span><span>O</span></span></span>
<span><span><span>Второе:</span></span></span>
<span><span><span>HNO3 + K2CO3 = HK2 + CO3NO3</span></span></span>
<span><span><span><span>HNO</span>3<span> + K</span>2<span>CO</span>3<span> = HK</span>2<span> + CO</span>3<span>NO</span>3</span></span></span>
Третье:
2HCl+MgО=MgCL2+H2O
2H(+)+2Cl(-)+MgО=Mg(+2)+2CL(-)+H2O
2H(+)+MgО=Mg(+2)+H2O
Четвёртое:
<span><span>3</span><span>K</span><span>O</span><span>H</span></span><span> + </span><span><span>Fe</span>(<span>N</span><span>O</span><span>3</span>)<span>3</span></span><span> = </span><span>3</span><span>K</span><span>N</span><span>O</span><span>3</span><span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span>
<span><span>3</span><span>K</span>+<span> + </span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> + </span><span>3</span><span>N</span><span>O</span><span>3</span>−<span> = </span><span>3</span><span>K</span>+<span> + </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+ </span><span>3</span><span>N</span><span>O</span><span>3</span>−</span>
<span><span>3</span><span>O</span><span>H</span>−<span> + </span><span>Fe</span>3+<span> = </span><span>Fe</span><span>(<span>O</span><span>H</span>)</span><span>3</span><span>+</span></span>
Пятое хз каак..
Шестое:
ZnSO4 +K3PO4=ZnSO4<span> +KOH</span>
1.вычислим массу чистой кислоты
m(CH3CH2COOH)=50*0.9=45g
45g xL
2CH3CH2COOH+Fe=Fe(CH3CH2COO)2+H2
148g 22.4L
x=45*22.4/148=6.8L
лови, думаю так))
ответ мой отметь как самый лучший))