9 + 30x - 100 = 2
30x = 102 - 9
30x = 93
x = 93/30
x = 3, 1
Решение
<span>Sin4xcosx-cos4xsinx>-√2/2
sin(4x - x) > - </span><span>√2/2
- arcsin( -</span>√2/2) + 2πk < 3x < π + arcsin(- √2/2) + 2πk, k ∈ Z
π/4 + 2πk < 3x < π - π/4 + 2<span>πk, k ∈ Z
</span>π/4 + 2πk < 3x < 3π/4 + 2<span>πk, k ∈ Z
</span>π/12 + 2πk/3 < 3π + 2<span>πk/3, k ∈ Z</span>
<span>Задание решено!!!Ответ во вложении!!</span>
11n+7, где n натуральное число
(1- sin x) (1+sin x) = 1^2 - sin^2 x = 1 - sin^2 x = cos^2 x