Пусть (х+1)^2=t
t^2+t-6=0
D=1+24=25
t1=-1+5/2=2
t2=-1-5/2=-3 не подходит
(х+1)^2=2
х+1=\/2 или х+1=-\/2
Ответ: х=\/2-1; х=-\/2-1
<span>1)а^3-2а^2-2а+4=a</span>²(a-2)-2(a-2)=(a-2)(a²-2)<span>
2)-у^6-у^5+у^4+у^3=-y^5*(y+1)+y</span>³(y+1)=(y+1)(-y^5+y³)=y³(1-y²)(y+1)=
<span>=y</span>³(1-y)(1+y)(y+1)=y³(1-y)(1+y)²<span>
3)х^2+2х-15=(x</span>²-3x)+(5x-15)=x(x-3)+5(x-3)=(x-3)(x+5)<span>
4)16ав^2-10с^3+32ас^2-5в^2с=16a(b</span>²+2c²)-5c(b²+2c²)=(b²+2c²)(16a-5c)<span>
7)3х^2+4х-7=(3x+7)(x-1)
8)2у^2-7у-9=(2x-9)(x+1)</span>
<span><span>4⁵-2х = 0,25
2х = 4⁵ - 0,25
х = (4⁵ - 0,25) / 2 = <span> (<span>1024 - 0,25 = 1023,75) / 2 = <span>511,875.
Можно по другому:
4</span></span></span>⁵ = 2¹⁰
0,25 = 1/4 = 1/2² = 2⁻²
2х = 2¹⁰ - 2⁻²
х = 2⁹ - 2⁻³ = <span><span> 512 - 0,125 = <span>511,875 </span></span></span></span></span>