Question

Помогите пожалуйста.срочно!!!!!!!!!!!!!!!!!!!=)

Answer 1

$\frac{6^{3+\sqrt5}}{2^{2+\sqrt5}\bullet3^{1+\sqrt5}}=\frac{6^3\bullet6^\sqrt5}{2^2\bullet2^\sqrt5}\bullet3^1\bullet3^\sqrt5}}=\frac{6^3}{2^2\bullet3}\bullet\frac{6^\sqrt5}{2^{\sqrt5}\bullet 3^\sqrt5}}=\\\\=18\bullet(\frac{6}{2\bullet3})^{\sqrt5-\sqrt5+\sqrt5}=18\bullet1^{-\sqrt5}=18.$