Question

Sin210°+cos420°-3×ctg300°=

Answer 1

Sin210°+cos420°-3×ctg300°=
= sin(210-180)+
+cos(420-360)-3×ctg(300-270)=
= -sin30+cos60-3×(-ctg30°)=
=-1/2+1/2-3(-√3/3)=√3/3