10x^2+9x-9 = 0
D = 81-4*(-9)*10 = 81+360 = 441 (кв. корень равен 21)
х1 = (-9+21)/20 = 12\20 = 3\5 = 0,6
х2 = (-9-21)/20 = -30\20 = -3\2 = -1,5
<u> ax^2+bx+c = a(x-x1)(x-x2)</u>
10(x - 0,6)(х+1,5) = (10x-6)(x+1,5)<u>
</u><u>10x^2+9x-9 = (10x-6)(x+1,5)</u><u>
</u>
X²(x+7)-4(x+7)=0
(x+7)(x²-4)=0
(x+7)(x+2)(x-2)=0
x+7=0⇒x=-7
x+2=0⇒x=-2
x-2=0⇒x=2
X²+3x-24=0 ; x²+3x=24 ; 5x=24 ; x=4,8
2х + 3y = - 1
3x + 5y = - 2
Решение
6х + 9y = - 3
- 6x - 10y = 4
- y = 1
y = - 1
2x + 3•( - 1 ) = - 1
2x = - 1 + 3
X = 2 : 2
X = 1
Ответ ( 1 ; - 1 )