Судя по программе алгоритм линейный
B) power(4, 2.5) + sqrt(1148.25 - power(1.1, 4)) / (156*cos(25*pi/180) + 2.6)
c) 148/abs(2.6 - power(1.4, 3)) + 18.1
2. √(ab) + 2a
---------------
b^2 + 2.3
3. var a: integer, V: integer
BEGIN
write ('Vvedite rebro a'); readln (a);
V = a*a*a;
writeln ('Ob'em kuba V = ', V);
END.
010000001000000011010111000010 000100101100000001000100010001010110000000010 100010010110000000110010100101000100100010111
var
<span> a,b,c:integer;
</span><span><span> begin
</span>
read(a,b,c);
</span><span> writeln(a,'+',b,'+',c,'=',a+b+c);
</span><span> writeln(a,'*',b,'*',c,'=',a*b*c);
</span><span> writeln('(',a,'+',b,'+',c,')/3=',(a+b+c)/3:4:3);
</span><span>
end.</span>