А.)CH4+Cl2(свет)=CH3Cl+HCl
2CH3Cl+2Na=2NaCl+CH3-CH3
C2H6+Cl2=C2H5Cl+HCl
2C2H5Cl+2Na=2NaCl+C4H10
C4H10(AlCl3)=CH3-CH-CH3
CH3
б)Al4C3+12H2O=4AL(OH)3+3CH4
CH4+Br2=CH3Br+HBr
2CH3Br+2Na=2NaBr+C2H6
C2H6=C2H4+H2
в.)CH3COOH + Na[HCO3]<span> → CH</span>3COONa+ H2O + CO<span>2
</span>CH3COONa(тв)+NaOH(тв)=сплав CH4+Na2CO3
CH4+HONO2=CH3NO2+H2O
Г.)C2H6+Br2=C2H5Br+HBr
2C2H5Br+2Na=2NaBr+C4H10
C4H10(AlCl3)=CH3-CH-CH3
CH3
Br
CH3-CH-CH3+Br2=HBr+CH3-CH-CH3
CH3 CH3
Ответ:
Бутадиен-1,2 СН2=С=СН-СН3
Бутадиен-1,3 СН2=СН-СН=СН2
Бутин-1 СН3-СН2-С≡СН
Объяснение:
C2H2n+HCl=CnH(2n+1)Cl
n(ню)=V/Vm
n=4.48/22.4=0.2 моль
n(CnH2n)=0.2 моль
n(CnH2n)=n(CnH(2n+1)Cl)
M=m/n
M(CnH(2n+1)Cl)=18.5/0.2=92.5
искомый алкен - бутен - C4H8
3SnCl₂ + K₂Cr₂O₇ <span>+ 14HCl = 3</span>SnCl₄ + 2CrCl₃ <span>+ 2KCl + 7H</span>₂<span>O
</span>Sn⁺²Cl₂⁻ + K₂⁺Cr₂⁺⁷O₇²⁻ + H⁺Cl⁻ = Sn⁺⁴Cl₄⁻ + Cr⁺³Cl₃⁻ + K⁺Cl⁻ + H₂⁺O²⁻
1 | 2 | Sn⁺² - 2e = Sn⁺⁴ | ок-е, вос-ль
2 | 4 | Cr⁺⁷ + 4e = Cr⁺³ | вос-е, ок-ль