Пусть число = х
Тогда другое = х + 2
Составим уравнение:
(х+2)^2 - x^2 = 24
x^2 +4x + 4 - x^2 = 24
4x = 20
x = 5
Проверка:
5 в квадрате = 25
7 в квадрате = 49
49 - 25 = 24
Ответ: 5
Значит
Ответ: а ∈ (-бесконечность; 2,5) U (2,5; +бесконечность).
<span>а)(1+3m)(1-3m)=1-9m^2</span>
<span><span>в)(2x-y)(2x+y)=4x^2-y</span></span>
<span><span><span>д)(4x+3y)(3y-4x)=-(4x+3y)(4x-3y)=-16x^2+9y^2</span></span></span>
<span><span><span><span>номер2</span></span></span></span>
<span><span><span><span><span>а)(x(^2)+2)(x(^2)-2)=x^4-4</span></span></span></span></span>
<span><span><span><span><span><span>в)(a(^2)-4)(a(^2)+4)=a^4-16</span></span></span></span></span></span>
<span><span><span><span><span><span><span>д)(ab-c)(ab+c)=a^2b^2-c^2</span></span></span></span></span></span></span>
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