Question

Log6 36+log2 32=? log6 36-log2 32=? log3 9+log2 8=? log3 9-log2 8=?

Answer 1

1) log6 36+log2 32= log6 6^2+log2 2^5 = 2+5=7
2) log6 36-log2 32 = log6 6^2-log2 2^5 = 2-5=-3
3) log3 9+log2 8 = log3 3^2+log2 2^3 = 2+3=5
4) log3 9-log2 8 = log3 3^2-log2 2^3 = 2-3=-1

Answer 2

6²=36, 2⁵=32, 3²=9, 2³=8

log₆36+log₂32=2+5=7
log₆36-log₂32=2-5=-3
log₃9+log₂8=2+3=5
log₃9-log₂8=2-3=-1