<span>1) (2х-3)(5х+1)-(х-6)(x+6)+13х=0</span>
<span>10x^2 + 2x- 15x- 3- x^2 + 36 + 13x =0</span>
<span>9x^2 +33 =0</span>
<span>9x^2=-33</span>
<span>3x^2=-11</span>
<span>2) <span>(2х-7)2-7(7-4х)=0</span></span>
8x-14-49+28x=0
<span>32x=63</span>
<span> <span>x=63/32</span></span>
<span><span>x=одна целая 31/32</span></span>
<span><span>3)<span>(х-5)2+5(2х-1)=0</span></span></span>
<span><span><span>2x-10+10x-5=0</span></span></span>
12x=15
4x=5
x=5/4
x=одна целая 1/4
<span>(х+3)(2-х)=0
х+3=0 или 2-х=0
х=-3 х=2
Ответ: -3 и 2</span>
а) х³ + 2х² + х + 2 = x²(x+2) + (x+2) = (x+2)(x²+1)
б) 4х - 4у + ху - у² = 4(x-y) + y(x-y) = (x-y)(4+y)
<span> 8ab+2a-20b-5 / 4ab-8b^2+a-2b= (8ab+2a)-(2ab+5)/(4ab+a)-(8b^2+2b)=2a(4b+1)-5(4b+1)/(a(4b+1)-2b(4b+1)=2a-5/a-2b</span>