Istina - предыдущее задание Вам написали неверно!!!
<span>KOH+HNO3 = KNO3 + H2O<span> </span></span><span>МОЛЕКУЛЯРНОЕ УРАВНЕНИЕ</span>
<span>K</span><span>+</span><span>+</span><span> OH</span><span>-</span><span> + </span><span>H</span><span>+</span><span> + </span><span>NO</span><span>-</span><span>3</span><span> = </span><span>K</span><span>+</span><span>+ </span><span>NO</span><span>-</span><span>3 </span><span>+ </span><span>H</span><span>2</span><span>O</span><span><span> </span></span><span>ПОЛНОЕ ИОННОЕ УРАВНЕНИЕ</span>
<span>H</span><span>+ </span><span>+ </span><span>OH</span><span>-</span><span><span> </span>= </span><span>H</span><span>2</span><span>O</span><span><span> </span>СОКРАЩЕННОЕ ИОННОЕ УРАВНЕНИЕ</span>
<span>2KOH + CuCl2 = 2KCl + Cu(OH)2 ↓ </span>
<span>2K++ 2OH- + Cu2+ + 2Cl- = 2K+ + 2Cl- + </span><span>Cu(OH)2 ↓</span>
<span>2OH- + Cu2+ = </span><span>Cu(OH)2 ↓</span>
<span> </span>
<span>Na2 CO3 + 2HNO3 = 2NaNO3 + CO2 ↑ + H2O</span>
<span>2Na+ + <span> </span>CO3 2- + 2H + + 2NO3- <span> </span>= 2Na++ 2NO3- + CO2 ↑ + H2O</span>
<span>CO3 2- + 2H + <span> </span>= CO2 ↑ + H2O</span>
<span> </span>
<span>Na2 CO3 + CuCl2 = 2NaCl + CuCO3↓</span>
<span>2Na+ + <span> </span>CO3 2- + </span><span>Cu2+ + 2Cl- = 2Na+ + 2Cl- + </span><span>CuCO3↓</span>
<span>CO3 2- + </span><span>Cu2+ = </span><span>CuCO3↓</span>
<span> </span>
<span>2</span><span>HNO</span><span>3</span><span> + </span><span>CuCl</span><span>2</span><span> = </span><span>Cu</span><span>(</span><span>NO</span><span>3</span><span>)2 + 2</span><span>HCl</span>
<span>2</span><span>H</span><span>+ </span><span>+ 2</span><span>NO</span><span>3</span><span>- </span><span><span> </span>+ </span><span>Cu</span><span>2+</span><span> + 2</span><span>Cl</span><span>- </span><span>= </span><span>Cu</span><span>2+</span><span> + </span><span>2</span><span>NO</span><span>3</span><span>-</span><span> + 2</span><span>H</span><span>+</span><span> + 2</span><span>Cl</span><span>-</span><span> только полное ионное ур-е, т.к. нет причины связывания ионов, сокращенного ур-я нет.</span>
<span> </span>