значение выражения 4z-5 и 14+4z противоположны, т.е.
14+4z=-(4z-5);
14+4z=-4z+5;
4z+4z=5-14;
8z=-9;
z=-9/8=-1.125
ответ: -1.125
Это смотря какой рисунок,какой построение
(7√19-√5)²+14(√95+3)=49×19-14√(19×5)+5+14√95+42=931+47-14√95+14√95=978
![8*16^{cosx}-6*4^{cosx}+1=0\\8*(4^{cosx})^2-6*4^{cosx}+1=0\\a=4^{cosx}\\8a^2-6a+1=0\\D=(-6)^2-4*8*1=36-32=4=2^2\\a_1= \frac{6+2}{2*8}= \frac{8}{16}= \frac{1}{2} ;\; \; \; a_2= \frac{6-2}{2*8}= \frac{4}{16}= \frac{1}{4}\\\\4^{cosx}= \frac{1}{2}\\2^{2cosx}=2^{-1}\\2cosx=-1\\cosx=-1/2\\x_1=б \frac{2 \pi }{3}+2 \pi n, n\in Z\\\\4^{cosx}= \frac{1}{4}\\4^{cosx}=4^{-1}\\cosx=-1\\x_2= \pi +2 \pi n, n\in Z\\\\\\](https://tex.z-dn.net/?f=8%2A16%5E%7Bcosx%7D-6%2A4%5E%7Bcosx%7D%2B1%3D0%5C%5C8%2A%284%5E%7Bcosx%7D%29%5E2-6%2A4%5E%7Bcosx%7D%2B1%3D0%5C%5Ca%3D4%5E%7Bcosx%7D%5C%5C8a%5E2-6a%2B1%3D0%5C%5CD%3D%28-6%29%5E2-4%2A8%2A1%3D36-32%3D4%3D2%5E2%5C%5Ca_1%3D+%5Cfrac%7B6%2B2%7D%7B2%2A8%7D%3D+%5Cfrac%7B8%7D%7B16%7D%3D+%5Cfrac%7B1%7D%7B2%7D+%3B%5C%3B+%5C%3B+%5C%3B+a_2%3D+%5Cfrac%7B6-2%7D%7B2%2A8%7D%3D+%5Cfrac%7B4%7D%7B16%7D%3D+%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C4%5E%7Bcosx%7D%3D+%5Cfrac%7B1%7D%7B2%7D%5C%5C2%5E%7B2cosx%7D%3D2%5E%7B-1%7D%5C%5C2cosx%3D-1%5C%5Ccosx%3D-1%2F2%5C%5Cx_1%3D%D0%B1+%5Cfrac%7B2+%5Cpi+%7D%7B3%7D%2B2+%5Cpi+n%2C+n%5Cin+Z%5C%5C%5C%5C4%5E%7Bcosx%7D%3D+%5Cfrac%7B1%7D%7B4%7D%5C%5C4%5E%7Bcosx%7D%3D4%5E%7B-1%7D%5C%5Ccosx%3D-1%5C%5Cx_2%3D+%5Cpi+%2B2+%5Cpi+n%2C+n%5Cin+Z%5C%5C%5C%5C%5C%5C+++++++++)
б) Находим корни уравнения на отрезке [3π/2; 3π]
x₁=2π+2π/3 = (6π+2π)/3=
8π/3 x₂=2π+π=
3π