Увеличить на ... это означает действие сложения
832+978=1810
2038+978=3016
89389+978=90367
![\frac{m}{-8} = \frac{-2}{4}= \frac{3}{n } \\ -\frac{m}{8} =- \frac{1}{2} \\ \frac{m}{8} = \frac{1}{2} \\ m=8*1:2=4 \\ n=-6](https://tex.z-dn.net/?f=+%5Cfrac%7Bm%7D%7B-8%7D+%3D+%5Cfrac%7B-2%7D%7B4%7D%3D+%5Cfrac%7B3%7D%7Bn+%7D++%5C%5C++-%5Cfrac%7Bm%7D%7B8%7D+%3D-+%5Cfrac%7B1%7D%7B2%7D++%5C%5C+%5Cfrac%7Bm%7D%7B8%7D+%3D+%5Cfrac%7B1%7D%7B2%7D++%5C%5C+m%3D8%2A1%3A2%3D4+%5C%5C+n%3D-6)
![\frac{-3}{m} = \frac{2}{-6} = \frac{n}{-3} \\ \frac{3}{m} = \frac{1}{3} = \frac{n}{3} \\ m=9 \ n=1](https://tex.z-dn.net/?f=+%5Cfrac%7B-3%7D%7Bm%7D+%3D+%5Cfrac%7B2%7D%7B-6%7D+%3D+%5Cfrac%7Bn%7D%7B-3%7D+%5C%5C+%5Cfrac%7B3%7D%7Bm%7D+%3D+%5Cfrac%7B1%7D%7B3%7D+%3D+%5Cfrac%7Bn%7D%7B3%7D+%5C%5C+m%3D9+%5C+n%3D1)
![\frac{-6}{2} = \frac{9}{m} = \frac{n}{-6} \\ -3 = \frac{9}{m} = \frac{n}{-6} \\ m=-3 \ n=18](https://tex.z-dn.net/?f=+%5Cfrac%7B-6%7D%7B2%7D+%3D+%5Cfrac%7B9%7D%7Bm%7D+%3D+%5Cfrac%7Bn%7D%7B-6%7D+%5C%5C+-3+%3D+%5Cfrac%7B9%7D%7Bm%7D+%3D+%5Cfrac%7Bn%7D%7B-6%7D+%5C%5C+m%3D-3+%5C+n%3D18)
![\frac{m}{-9} = \frac{-6}{n} = \frac{4}{6} \\ \frac{m}{-9} = \frac{-6}{n} = \frac{2}{3} \\ m=-6 \ n=-9](https://tex.z-dn.net/?f=+%5Cfrac%7Bm%7D%7B-9%7D+%3D+%5Cfrac%7B-6%7D%7Bn%7D+%3D+%5Cfrac%7B4%7D%7B6%7D+%5C%5C++%5Cfrac%7Bm%7D%7B-9%7D+%3D+%5Cfrac%7B-6%7D%7Bn%7D+%3D+%5Cfrac%7B2%7D%7B3%7D+%5C%5C+m%3D-6+%5C+n%3D-9)
AC(0-0;2-4;5+1)=(0;-2;6)
CB(1-0;3-2;0-5)=(1;1;-5)
AC-CB=(0-1;-2-1;6+5)=(-1;-3;11)
|AC-CB|=
![\sqrt{(-1)^2+(-3)^2+11^2}](https://tex.z-dn.net/?f=+%5Csqrt%7B%28-1%29%5E2%2B%28-3%29%5E2%2B11%5E2%7D+)
=√1+9+121=√131
AB(-3-1;-1+1;2-0)=(-4;0;2)
CB(-3+1;-1-2;2-1)=(-2;-3;1)
AB-CB=(-4+2;0+3;2-1)=(-2;3;1)
|AB-CB|=
![\sqrt{(-2)^2+3^2+1^2}](https://tex.z-dn.net/?f=+%5Csqrt%7B%28-2%29%5E2%2B3%5E2%2B1%5E2%7D)
=√4+9+1=√14
287+(120-х)=300
120-х=300-287
120-х=13
х=120-13
х=107
8 т 6 ц 7 кг = 8607 кг . Это больше 2989 кг на 5618 кг или 5 т 6 ц 18 кг