Дано:
![q_{1} = q_{2} = q](https://tex.z-dn.net/?f=q_%7B1%7D+%3D+q_%7B2%7D+%3D+q)
![\varepsilon = 1](https://tex.z-dn.net/?f=%5Cvarepsilon+%3D+1)
![r = 4 \ \text{c}_{\text{M}} = 0,04 \ _{\text{M}}](https://tex.z-dn.net/?f=r+%3D+4+%5C+%5Ctext%7Bc%7D_%7B%5Ctext%7BM%7D%7D+%3D+0%2C04+%5C+_%7B%5Ctext%7BM%7D%7D)
![F = 6 \ _{\text{M}}\text{H}=6 \ \cdotp 10^{3} \ \text{H}](https://tex.z-dn.net/?f=F+%3D+6+%5C+_%7B%5Ctext%7BM%7D%7D%5Ctext%7BH%7D%3D6+%5C+%5Ccdotp+10%5E%7B3%7D+%5C+%5Ctext%7BH%7D)
![k = 9 \ \cdotp 10^{9} \ \dfrac{\text{H} \ \cdotp _{\text{M}^{2}}}{\text{K}_{\Lambda ^{2}}}}}](https://tex.z-dn.net/?f=k+%3D+9+%5C+%5Ccdotp+10%5E%7B9%7D+%5C+%5Cdfrac%7B%5Ctext%7BH%7D+%5C+%5Ccdotp+_%7B%5Ctext%7BM%7D%5E%7B2%7D%7D%7D%7B%5Ctext%7BK%7D_%7B%5CLambda+%5E%7B2%7D%7D%7D%7D%7D)
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Найти:![q - ?](https://tex.z-dn.net/?f=q+-+%3F)
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Решение. По закону Кулона
Отсюда ![q = \sqrt{\dfrac{F \varepsilon r^{2}}{k}} = r \sqrt{\dfrac{F \varepsilon}{k}}](https://tex.z-dn.net/?f=q+%3D+%5Csqrt%7B%5Cdfrac%7BF+%5Cvarepsilon+r%5E%7B2%7D%7D%7Bk%7D%7D+%3D+r+%5Csqrt%7B%5Cdfrac%7BF+%5Cvarepsilon%7D%7Bk%7D%7D)
Определим значение искомой величины:
![[q] = \ _{\text{M}} \ \cdotp \sqrt{ \dfrac{\text{H} \ \cdotp \text{K}_{\Lambda ^{2}}}{\text{H} \ \cdotp _{\text{M}^{2}}}} = \ _{\text{M}} \ \cdotp \sqrt{ \dfrac{\text{K}_{\Lambda ^{2}}}{_{\text{M}^{2}}}} = \dfrac{_{\text{M}} \ \cdotp \text{K}_{\Lambda}}{_{\text{M}}} = \text{K}_{\Lambda}](https://tex.z-dn.net/?f=%5Bq%5D+%3D+%5C+_%7B%5Ctext%7BM%7D%7D+%5C+%5Ccdotp+%5Csqrt%7B+%5Cdfrac%7B%5Ctext%7BH%7D+%5C+%5Ccdotp+%5Ctext%7BK%7D_%7B%5CLambda+%5E%7B2%7D%7D%7D%7B%5Ctext%7BH%7D+%5C+%5Ccdotp+_%7B%5Ctext%7BM%7D%5E%7B2%7D%7D%7D%7D+%3D+%5C+_%7B%5Ctext%7BM%7D%7D+%5C+%5Ccdotp+%5Csqrt%7B+%5Cdfrac%7B%5Ctext%7BK%7D_%7B%5CLambda+%5E%7B2%7D%7D%7D%7B_%7B%5Ctext%7BM%7D%5E%7B2%7D%7D%7D%7D+%3D+%5Cdfrac%7B_%7B%5Ctext%7BM%7D%7D+%5C+%5Ccdotp+%5Ctext%7BK%7D_%7B%5CLambda%7D%7D%7B_%7B%5Ctext%7BM%7D%7D%7D+%3D+%5Ctext%7BK%7D_%7B%5CLambda%7D)
![q = 0,04 \ \cdotp \sqrt{\dfrac{6 \ \cdotp 10^{3} \ \cdotp 1}{9 \ \cdotp 10^{9}}} = 0,04 \ \cdotp \sqrt{ \dfrac{2 \ \cdotp 10^{-6}}{3}} \approx 4 \ \cdotp 10^{-2} \ \cdotp 8 \ \cdotp 10^{-4} = 32 \ \cdotp 10^{-6} \ \text{K}_{\Lambda}](https://tex.z-dn.net/?f=q+%3D+0%2C04+%5C+%5Ccdotp+%5Csqrt%7B%5Cdfrac%7B6+%5C+%5Ccdotp+10%5E%7B3%7D+%5C+%5Ccdotp+1%7D%7B9+%5C+%5Ccdotp+10%5E%7B9%7D%7D%7D+%3D+0%2C04+%5C+%5Ccdotp+%5Csqrt%7B+%5Cdfrac%7B2+%5C+%5Ccdotp+10%5E%7B-6%7D%7D%7B3%7D%7D+%5Capprox+4+%5C+%5Ccdotp+10%5E%7B-2%7D+%5C+%5Ccdotp+8+%5C+%5Ccdotp+10%5E%7B-4%7D+%3D+32+%5C+%5Ccdotp+10%5E%7B-6%7D+%5C+%5Ctext%7BK%7D_%7B%5CLambda%7D)
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Ответ:![q = 32 \ _{\text{MK}}\text{K}_{\Lambda}](https://tex.z-dn.net/?f=q+%3D+32+%5C+_%7B%5Ctext%7BMK%7D%7D%5Ctext%7BK%7D_%7B%5CLambda%7D)
Решение во вложении. Удачи.
Ответ : 90 {<em>секу</em><em>нд</em>}
2) A=P*t=1300*10^3*180=234*10^6 Дж=234 кДж
3) V=P/m=250/0,95=263,2 м/с
4) m1*V1=m1*V+m2*V m2=m1*(V1-V)/V1=2*(1,8-1,2)/1,2=1 кг
5) Ek=m*(h1-h1)=0,4*(5-3)=0,8 м/с
Самолет должен двигаться с ускорением свободного падения при любой начальной скорости