Дано
Mg
m(H2SO4)=10g
Найти
V(H2)-?
10g Xл
Mg+H2SO4-->MgSO4+H2↑
98 22.4
M(H2SO4)=98g/mol , Vm=22.4L/mol
10/98 = X/22.4 X=2.29 л
ответ 2.29 л
2Ca3(PO4)2 + 10C + 6SiO2 = 6CaSiO2 + P4 + 10CO
4P + 5O2 = 2P2O5
P2O5 + Ca(OH)2 + H2O = Ca(H2PO4)2
Ca(H2PO4)2 +2Ca(OH)2= Ca3(PO4)2 + 4H2O
Ca²⁺+ CO₃²⁻= CaCO₃↓
Ca²⁺ + 2CI⁻ + 2Na⁺+ CO₃²⁻ = CaCO₃↓ + 2Na⁺ + 2CI⁻<span>
CaCI</span>₂ + Na₂CO₃ = CaCO₃↓ + 2NaCI
<span>
Al</span>₂O₃+6H⁺=2Al³⁺+3H₂O
AI₂O₃ + 6H⁺ + 3SO₄²⁻ = 2AI³⁺ +3SO₄²⁻ + 3H₂O<span>
AI</span>₂O₃ + 3H₂SO₄ = AI₂(SO₄)₃ + 3H₂O
<span>
Ba</span>²⁺ + SO₄²⁻ = BaSO₄↓
Ba²⁺ + 2CI⁻ + 2H⁺ + SO₄²⁻ = BaSO₄↓ + 2H⁺ + 2CI⁻
BaCI₂ + H₂SO₄ = BaSO₄↓ + 2HCI
NiSO₄+(NH₄)₂S=(NH₄)₂SO₄ + NiS↓
Ni²⁺+ SO₄²⁻ + 2NH₄⁺ + S²⁻ = 2NH₄⁺ + SO₄²⁻ + NiS↓
Ni²⁺ + S²⁻ = NiS↓
Дано:
<span>V (H2) =
15 л
</span>
<span>w(HCl) = 10%</span>
<span>
</span>
Найти:
<span>m(р-ра
HCl)</span>
Решение:
<span> x г 15 л</span>
<span>Fe
+ 2HCl = H2↑+ FeCl2
</span>
<span> 73 г 22,4 л
</span>
х г --- 15 л
73 г --- 22,4 л
х = 73 г ∙ 15 л\22,4 л = 48,88 г
<span>m(р-ра HCl)
= m(р.в.) ∙ 100%\ w(р-ра) = 48,88 г ∙ 100%\10% = 488,8г</span>
<span>ответ: m(р-ра
HCl) = 488,8 г</span>
Ar(H) = 1
Ar(O) = 16
2Н2 + О2 = 2Н2О
<span>4 : 32 = 1 : 8</span>