53734/67=802
802*18=14436
40100+14436=54536
54536-4536=50000
и
18324/36=509
509*40=20360
108000-20360=87640
87640+7840=95480
21:3=7 мешков за 1 день 7 осликов, 7:7=1мешок за 1 день 1 ослику, 5*1=5мешков за 1 день 5 осликов, 5*5=25 мешков за 5 дней 5 осликов Ответ: 25 мешков
![f(x)=- \frac{1}{3}x^3+x^2-1 \ \ => \ \ f'(x)=-x^2+x \\ x(1-x)>0 \ \ <=> \ \ x \in (0,1) \\ => \ \ f'(x)>0 \ \ <=> \ \ x\in(0,1)](https://tex.z-dn.net/?f=f%28x%29%3D-+%5Cfrac%7B1%7D%7B3%7Dx%5E3%2Bx%5E2-1+%5C+%5C+%3D%3E+%5C+%5C+f%27%28x%29%3D-x%5E2%2Bx+%5C%5C%0Ax%281-x%29%3E0+%5C+%5C+%3C%3D%3E+%5C+%5C+x+%5Cin+%280%2C1%29+%5C%5C%0A%3D%3E+%5C+%5C+f%27%28x%29%3E0+%5C+%5C+%3C%3D%3E+%5C+%5C+x%5Cin%280%2C1%29+)
Итого:
![f](https://tex.z-dn.net/?f=f)
возрастает на
![(0,1)](https://tex.z-dn.net/?f=%280%2C1%29)
и убывает на
![|R\setminus(0,1)](https://tex.z-dn.net/?f=%7CR%5Csetminus%280%2C1%29)
![f(x)=x^3-9x^2-24x-12 \ \ => \ \ f'(x)=3x^2-18x-24 \ \ => \\ => \ \ f''(x)=6x-18=6(x-3) \\ 6(x-3)>0 \ \ <=> \ \ x>3 \\ f''(x)>0 \ \ <=> \ \ x>3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3-9x%5E2-24x-12+%5C+%5C+%3D%3E+%5C+%5C+f%27%28x%29%3D3x%5E2-18x-24+%5C+%5C+%3D%3E+%5C%5C%0A%3D%3E+%5C+%5C+f%27%27%28x%29%3D6x-18%3D6%28x-3%29+%5C%5C%0A6%28x-3%29%3E0+%5C+%5C+%3C%3D%3E+%5C+%5C+x%3E3+%5C%5C%0Af%27%27%28x%29%3E0+%5C+%5C+%3C%3D%3E+%5C+%5C+x%3E3)
Итого: выпуклое множество на
![x>3](https://tex.z-dn.net/?f=x%3E3)
Ответ:
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Пошаговое объяснение: