230 г х л
46 г 22,4 л
При взаимодействии 46 г натрия выделяется 22,4 л водорода, а
при -- // -- 230 г_________________х л, откуда
х=230*22,4/46= <span>112 л</span>
A)<span>CH4+ Cl2-->CH3Cl+HCl
б)</span>CH3Cl + Cl2 = CH2Cl2 + HCl
в)<span>2CH3Cl+2Na-->C2H6+2NaCl
г)</span><span>C2H6+2O2 = 2CO2 + 3H2
д)</span><span>C2H6 + Br2 = C2H5Br + HBr</span>
3C2H2+8KMnO4=3K2C2O4+8MnO2+2KOH+2H2O
<span>Ca+<span>2<span>H2IO</span></span> → <span>Ca<span>(OH)</span>2</span>+<span>H2
</span></span><span><span>Ca<span>(OH)</span>2</span>+<span>H2CO3</span> → <span>CaCO3</span> +<span>2<span>H2O
</span></span></span><span><span>CaCO3</span> → <span>CaO</span>+<span>CO2
</span></span><span><span>CaO</span>+<span>2<span>HCl</span></span> → <span>CaCl2</span>+<span>H2O
</span></span><span><span>Na2CO3</span> +<span>CaCl2</span> → <span>2<span>NaCl</span></span>+<span>CaCO<span>3
</span></span></span>