Решение
1) sinx = - 1/2
x = (-1)^n *arcsin(-1/2) + πn, n ∈ Z
x = (-1)^(n+1) *arcsin(1/2) + πn, n ∈ Z
x = (-1)^(n+1) *(π/6)<span> + πn, n ∈ Z
</span>2) 3tgx = 0
tgx = 0
x = πk, k ∈ Z
3) cos4x = 0
4x = π/2 + πn, n ∈ Z
x = π/8 + (πn)/4, n ∈ Z
4) cos(3x - π/6) = - 1
3x - π/6 = π + 2πk, k ∈ Z
<span>3x = π/6 + π + 2πk, k ∈ Z
</span>3x = 7π/6 + <span>2πk, k ∈ Z
x = 7</span>π/18 + (2πk)/3, k ∈ Z
V=π∫( от π\4 до π\2)сos²xdx=π(cos³x)\3( от π\4 до <span>π\2)=
</span>π\3(cos³π\2-<span>cos³</span>π\4)=π\3(0-√2\4)=3√2\12
9 остр. 6 остр.
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