<span>Cм = ω%*p*10/M = 33,50*1,325*10/56 = 7,93 М
M = 39 + 16 + 1 = 56 г/моль
Cм = m</span>₁/M₁*V₂(л)
ω% = m₁*100%/m₂
m₂ = p(г/мл)*V₂(мл)
раствор - 2
вещество - 1
ω% = m₁*100%/<span>p*V₂
</span>m₁ = ω%*p*V₂/<span>100%
</span>Cм = ω%*p*V₂*1000/M₁*V₂*100 = ω%*p*10/M₁
Решение:
kt,t
С2H6<em>---></em>C2H4+H2
kt,t
C2H4<em>---></em>C2H2+H2
t/C
3C2H2<em>---></em>C6H6
AlCl3
C6H6+Br2<em>------></em>C6H5Br + HBr
СuCO3+2HCl=CuCl2+H2O+CO2
cuco3+ 2h+ →cu2+ +h2o+co2
CuCl2+2Na(OH)=Cu(OH)2+2NaCl
cu2+ + 2oh- → cu(oh)2
Cu(OH)2+H2SO4=CuSO4+2H2O
cu(oh)2 → 2h2o+ cu2+
СuCO3+2NaOH→Cu(OH)2+Na2CO3
cuco3+ 2oh- → cu(oh)2 + co3^2-
CuCO3+2HCl → cucl2 + h2o + co2↑
cuco3 + 2H+→cu2+ + h2o + co2
Fe+H2SO4→ FeSo4+h2