Дано
m(Mg)=7.2 g
m(ppa HCL)=200 g
W(HCL)=30%
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m(MgCL2)-?
m(HCL)=m(ppa HCL)*W(HCL)/100% = 200*30%/100% = 60 g
M(Mg)=24 g/mol
n(Mg)=m/M=7.2/24 = 0.3 mol
M(HCL)=36.5 g/mol
n(HCL)=m/M = 60/36.5 = 1.64 mol
n(Mg)<n(HCL)
Mg+2HCL-->MgCL2+H2
n(Mg)=n(MgCL2)=0.3 mol
M(MgCL2) = 97 g/mol
m(MgCL2)=n*M = 0.3*97 = 29.1 g
ответ 29.1 г
------- х л 13,35 г
2Al + 3Cl2 = 2AlCl3
------- 67,2 л 267 г
х:67,2=13,35:267
х= 3,36 л
Ответ: 3,36 л
CH₃
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H₃C - C = C - C = C - CH₃ 2,3,4- триметил гексадиен-2,4
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CH₃ CH₃