1) 4(х^2-2ху+у^2)=4x^2 - 8 xy +4y^2
По формуле <u>a^2 - b^2 = (a - b)* (a + b)
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(x-2)^2 - (x+3)^2 = 0 </span>
(x - 2 - (x + 3)) * (x - 2 + x + 3) = 0
(x- 2 - x - 3) * ( x - 2 + x + 3)= 0
- 6* (2x + 1) = 0
2x = - 1
x = - 1/2 = - 0 .5
X6=x3-125
x6-x3=-125
x3=-125
x=-5