Ответ:
6.
Mr(FeSO₄)=56+32+4x16=152
Мr(H₂SO₄) =2+32+64=98
Mr[Cu(OH) ₂]=64+(17x2)=98
7.
Mr(NaCI)=Ar(Na)+Ar(CI)=23+35,5=58,5
ω(Na)=23÷58,5=0,3932 ω%(Na)=ω(Na)×100%=0,3931×100%=39,32%
ω(CI)=35,5÷58,5=0,6068 ω%(CI)=ω(CI)×100%=0,6068×100%=60,68%
Mr(C₃H₈)=3Ar(C)+8Ar(H)=3×12+8×1=36+8=44
ω(C)=36÷44=0,8182 ω%(C)=ω(C)×100%=0,8182 ×100%=81,82%
ω(H)=8÷44=0,1818 ω%(H)=ω(H)×100%=0,1818×100%=18,18%
Mr(SF₆)=Ar(S)+6Ar(F)=32+9×6=32+54=86
ω(S)=32÷86=0,3721 ω%(S)=ω(S)×100%=0,3721 ×100%=37,21%
ω(F)=54÷86=0,6279 ω%(F)=ω(F)×100%=0,6279×100%=62,79%