Question

Решите систему пожалуйста

Answer 1

$\left \{ {{ \frac{2x+1}{5 }= \frac{y-1}{2}} \atop {4x+5y=23}\right.==\ \textgreater \ \left \{ {{ \frac{2(2x+1)}{10}= \frac{5(y-1)}{10} } \atop {4x+5y=23} \right. ==\ \textgreater \ \left \{4x+2=5y-5} \atop {4x+5y=23}} \right. ==\ \textgreater \ \left \{4x-5y=-7} \atop {4x+5y=23}} \right.$$==\ \textgreater \ \left \{ {8x=16} \atop {4x+5y=23} \right. ==\ \textgreater \ \left \{ {x=2} \atop {4*2+5y=23}} \right. ==\ \textgreater \ \left \{ {{x=2} \atop {5y=23-8=15}} \right. ==\ \textgreater \ \left \{ {{x=2} \atop {y=15:5=3}} \right.$
( x;у ) = ( 2;3 )

Answer 2

Исходные не пишу
4х+2=5у-5
4х+5у=23
4х-5у=-7
4х+5у=23
сложим
8х=16
х=2
у=(23-4х):5=3