Question

Log0,2*125:log16*64*log3*81=?

Answer 1

$\log_{0,2}125:\log_{16}64\cdot\log_381=(-3):\log_{4^2}64\cdot4=(-3):\frac12\log_464\cdot4=\\=(-3):(\frac12\cdot3)\cdot4=(-3):\frac32\cdot4=-3\cdot\frac23\cdot4=-2$