Y=log0.5(х²−10х+29) х²−10х+29>0 D=100-4*29=100-116=-16=>
х²−10х+29>0 при любом x<span>
y`=(</span><span>log0.5(х²−10х+29))`*(x^2-10x+29)`=-ln0,5/x*(2x-10)=-ln0,5(2x-10)/x
</span>-ln0,5(2x-10)/x=0 x≠0
(2x-10)/x=0
(x-5)/x=0
x=5
+ 0 - 5 +
xmax=5
ymax=log0,5(5^2-10*5+29)=log0,5(25-50+29)=log0,5(4)=-2
а) 3/4 * 5/7 = 15/28
б) 1/8 * 3/4 = 3/32
в) 4/7 * 5/6 = 20/42 = 10/21
г) 2/5 * 7/11 = 14/55
д) 1/2 * 4/9 = 4/18 = 2/9
е) 11/12 * 8/9 = 88/108 = 22/27
ж) 2/5 * 3/2 = 3/5
з) 11/15 * 3/5 = 11/5 * 1/5 = 11/25
и) 15/16 * 5/9 = 75/45 = 15/9 = 1целая6/9
6p-531=405
6p=936
p=156
875/n=25
n=875/25
n=35
1)9а
2)24b
3)15x
4)13y
5)9с
6)18а
7)20 к
8)32d или же 17d=15
составляем дробь
d=15/17