<span>(x^2+2x)^2-(x+1)^2-55=0
(x</span>²+2x)²-(x²+2x+1)²-55=0
x²+2x=t
t²-(t+1)²-55=0
t²-t²-2t-1-55=0
2t=-56
t=-28
x²+2x=28
x²+2x-28=0
D=4+112=116
x1=(-2-2√29)/2=-1-√29 U x2=-1+√29
(x-1)(x+1)/(x-2)(x+2)*5x+10/x-1=
x+1/(x-2)(x+2)*5(x+2)=
x+1/x-2*5=
5(x+1)/x-2=
5x+5/x-2
Ответ:5x+5/x-2