<span>В какой из реакций можно получить только хлорид алюминия 2)Al2O3</span>
CuO + H2 = Cu + H2O
n(Cu) = m/M = 3.2/64 = 0.05 моль
Из уравнения реакции:
n(H2) = 0.05*1/1 = 0.05 моль
V(H2) = n*Vm = 0.05*22.4 = 1.12 л
m(H2) = n*M = 0.05*2 = 0.1 г
Na2CO3+2HNO3=2NaNO3+H2O+CO2
FeCl3+3HNO3=Fe(NO3)3+3HCl
<span><span>3<span>Na2S</span></span>+<span>8<span>HNO3=</span></span><span>6<span>NaNO3</span></span>+<span>2<span>NO</span></span>+<span>3S</span>+<span>4<span>H2O
</span></span></span><span><span>3 <span>Na2S</span></span>+<span>2<span>FeCl3=</span></span><span>2<span>FeS</span></span>+S+<span>6<span>NaCl</span></span></span>
SO3+H2O=H2SO4
<span><span>H2SO4</span>+<span>H2O=</span><span>H2OSO4</span> + <span>H2
</span></span>2KI+H2O=K2O+2HI
<span><span>8<span>KI</span></span>+<span>5<span>H2SO4=</span></span><span>4<span>I2</span></span>+<span>4<span>K2SO4</span></span>+<span>H2S</span>+<span>4<span>H2<span>O</span></span></span></span>
Ответ:
Посмотри в таблице сзади учебника