M(соли)=x*y/100
V(воды)=x-x*y/100=x*(1-y/100)
Паред 2Н2О и все уравнялось!
H3PO4 + NaOH = NaH2PO4 + H2O
H3PO4 + 2NaOH = Na2HPO4 + 2H2O
H3PO4 + 3NaOH = Na3PO4 + 3H2O
2H3PO4 + 3CaO = Ca3(PO4)2 + 3H2O
Дано
W(C)=36.9% = 0.369
W(H) = 4.6%=0.046
W(F)=58.5% = 0.585
M(CxHyFz)=130 g/mol
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CxHyFz-?
CxHyFz / 130 = 0.369 / 12 : 0.046 / 1 : 0.585 / 19
CxHyFz = 4 : 6 : 4
C4H6F4 M(C4H6F4)=12*4 + 1*6 + 19 * 4 =130 g/mol
ответ C4H6F4
M(CxHy) = 35*2= 70 г
m(Cx) = 70*0.8571 = 60 г
m(Hy) = 70* 0.1429 = 10 г
n(C)= 60 /12=5 моль
n(H) = 10 / 1 = 10 моль
С : H = 5 : 10
C5H10