Question

Ннчетные ))
337 1,3,5

Answer 1

№337  (1,3,5)
$\frac{(x-y)^2 }{2x-2y} = \frac{(x-y)^2}{2(x-y) } = \frac{x-y}{2}$

$\frac{-a(b-n)^3}{ab-an} = \frac{-a(b-n)^3}{a(b-n)} = \frac{-1*(b-n)^2}{1} = - (b-n) ^{2}$

$\frac{24a^2-60ab}{12ab-30b^2} = \frac{12a( 2a-5b)}{6b(2a-5b)} = \frac{2a}{b}$


(х-у)² / (2х-2у) = (х-у)²/ ( 2*(х-у)) = (х-у)/2
(-а (b-n)³) / (ab-an)  =  (-a(b-n)³) /  (a (b-n) ) =  (-1 *(b-n)² ) / 1  = - (b-n)²
(24a²-60ab) / (12ab-30b²) =  (12a (2a-5b)) / (6b(2a-5b) ) = 2a / b