P3N5 + 30H2 = 3P4 + 20NH3
происходит выделение простого вещества P4 (белый фосфор) и азотной кислоты.
1)HCOOH+CH3OH --> HCOOCH3+H2O (метилформиат)
2)HCOOH+C2H5OH --> HCOOC2H5+H2O (этилформиат)
3)HCOOH+C3H7OH --> HCOOC3H7+H2O (этилпропианат)
Смысыл прост, в группе OH водород замещается на алкильный радикал, при этом вода выделяется
SiO2 + C = CO2 + Si
2Mg + Si = Mg2Si
Mg2Si + 4HCl = 2MgCl2 + SiH4
SiH4 = Si + 2H2
14
а 2 CO2 + C = 2CO 2C + Ca = CaC2
б 3 H2SO3 + Na2O = Na2SO3 + H2O <span><span>3 <span>Na2O</span></span> + <span>P2O5</span> → <span>2 <span>Na3PO<span>4
</span></span></span></span>в 1 <span><span>NH4Cl</span> + <span>NaOH</span> = <span>NH3</span></span>↑<span> + <span>H2O</span> + <span>NaCl </span></span>NH4Cl + AgNO3 = AgCl↓ + NH4NO3
15
а
б 1 <span><span>SiO2</span> + <span>2 <span>KOH</span></span> = <span>K2SiO3</span> + <span>H2O </span></span><span> СаСО3 + </span>SiO2<span> = CaSiO3 + CO2</span>
в 4 <span><span>SO2</span> + <span>Ca<span>(OH)</span>2</span> = <span>H2O</span> + <span>CaSO3 </span></span><span><span>Ca<span>(OH)</span>2</span> + <span>2 <span>HCl</span></span> = <span>CaCl2</span> + <span>2 <span>H2O
16
a 4 2H2SO4 + S = 3SO2 + 2H2O S + O2 = SO2
б 2 </span></span></span> 2NaOH + ZnO = Na2ZnO2 + H2O(cплавление)
<span><span>ZnO</span> + <span>2 <span>HCl</span></span> → <span>ZnCl2</span> + <span>H2<span>O
</span></span></span>в 3 <span><span>AlCl3</span> + <span>3 <span>AgNO3</span></span> = <span>3 <span>AgCl</span></span> + <span>Al<span>(NO3)</span>3 </span></span><span><span>AlCl3</span> + <span>3 <span>KOH</span></span> = <span>Al<span>(OH)</span>3</span> + <span>3 <span>KCl
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Кто владеет информацией, тот владеет миром.
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