Вроде как во всех кроме нуля, но я затрудняюсь, вы уверенны что там нет скобок?
<span><span><span><span><span><span>A</span><span>B</span><span>=</span><span>A</span><span>C</span><span>c</span><span>o</span><span>s</span><span><span><span><span>30</span></span><span><span>0</span></span></span></span><span>=</span><span><span><span><span><span>3</span></span></span><span><span>√</span></span></span></span><span><span><span>/</span></span></span><span>2</span><span>,</span><span>B</span><span>C</span><span>=</span><span>A</span><span>C</span><span>s</span><span>i</span><span>n</span><span><span><span><span>30</span></span><span><span>0</span></span></span></span><span>=</span><span>1</span><span><span><span>/</span></span></span><span>2</span><span>,</span><span>B</span><span>D</span><span>=</span><span><span><span><span><span>A</span><span>B</span><span>⋅</span><span>B</span><span>C</span></span></span><span><span><span>A</span><span>C</span></span></span></span></span><span>=</span><span><span><span><span><span>3</span></span></span><span><span>√</span></span></span></span><span><span><span>/</span></span></span><span>4</span></span></span></span></span></span>
Ответ:
Пошаговое объяснение:
A) sin(π/2 + t) = √3/2
cos(t) = √3/2
t = +- π/3 + 2πk, k∈Z
Б) 2cos²t + sint + 1 = 0
2 - 2sin²t + sint + 1 = 0
2sin²t - sint - 3 = 0
D = 1 + 24 = 25
sint = (1 + 5)/4 = 3/2 > 1 - не подходит
sint = (1 - 5)/4 = -1
t = -π/2 + 2πk, k∈Z