=(5кор(2))^2=25*2=50; Ответ: 50
По определению модуля
8 - 0.2x = ±12
-0.2x = 12 - 8 или -0.2x = 12 + 8
-0.2x = 4 -0.2x = 20
x = -20 x=-100
Ответ: -100; -20.
A) D=169+120=289
x1= (-13+17)/6=0.3
X2=(-13-17)/6= -5
b) x(2x-3)=0, x1=0, X2=3/2=1.5
v) 16x^2-49=0, (4x-7)(4x+7)=0
4x-7=0, x1=1.75, 4x+7=0 X2= -1.75
г) x^2-2x-35=0
D=4+140=144
x1=(2+12)/2=7, X2=(2-12)/2= -5
д) D=49+32=81, x1=(7+9)/2=8
X2=(7-9)/2= -1
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