1)х+3>=0, х>=-3 и 7-2х>=0, 2х=<7, х=<3,5
[-3;3,5]
2)х-3>=0, х>=3 и х>=0
[0;3]
вроде так
4M + [ ( 1 - 6M^2 ) / M ] = ( 4M^2 + 1 - 6M^2 ) / M = ( 1 - 2M^2 ) /M
M = 2
( 1 - 8 ) / 2 = ( - 7 ) / 2 = ( - 3,5 )
<span>Sin^2x+√3Sinx Cosx=o
Sin</span>²<span>x+</span>√3SinxCosx =0
Sinx(Sinx +√3Cosx) = 0
Sinx = 0 или Sinx +√3Cosx = 0 | : Cosx
x = πn , n ∈Z tgx +√3 = 0
tgx = -√3
x = -π/3 + πk , k ∈Z
Два решения
2x=-10-8
2x=-18
x=-9
2x=10-8
2x=2
x=1