A^2-3a , при а=5,6,0.1
5^2-3*5= 25-15=10
-6^2-3*(-6)=-36+18=-18
0.1^2-3*0.1=0.1^2-0.3
2)log12(27)=a;log6(16)=?
log12(3^3)=3•log3(3)/log3(12)=3/(log3(3)+2log3(2))=3/(1+2log3(2))=a
3=a+2alog3(2)
log3(2)=(3-a)/2a
log6(16)=4log6(2)=4•log3(2)/log3(6)=
4log3(2)/(1+log3(2))=4(3-a)/2a:(1+(3-a)/2a)=
2(3-a)/a:(a+3)/2a=2(3-a)/a*2a/a+3=
4(3-a)/(3+a)
3)a)log30(x)=1/logx(30)=
1/(logx(5)+logx(2)+logx(3))
b)1/(log2(x)•log3(x)•log5(x))
*1/(logx(5)+logx(2)+logx(3))=
log2(x)•log3(x)+log3(x)•
log5(x)+log5(x)•log2(x)
c)(log2(x)•log3(x)+log3(x)•
log5(x)+log5(x)•log2(x)):
(log2(x)•log3(x)+log3(x)•
log5(x)+log5(x)•log2(x))
=1
а = 75 + 0.75в, а = 75 + 0.75(50 + 0.5а), а = 75 + 37.5 + 0.375а,
в = 50 + 0.5а; в = 50 + 0.5а; в = 50 + 0.5а;
0.625а = 112.5, а = 180, а = 180,
в = 50 + 0.5а; в = 50 + 90; в = 140.
-х-у=+6=0
-х-у=-6/-1
х+у=6.
Вроде так,но я не уверена.