б)<span> ℓog2x+3(5x2+11x+3)=2</span>
<span>5x²+11x+3=(2x+3)²</span>
<span>5x²+11x+3=4x²+12x+9</span>
<span>5x²+11x+3-4x²-12x-9=0</span>
<span>x²-x-6=0</span>
<span>D = 1²-4*1*(-6)=1+24=25</span>
<span>x1=(1+5)/2=3</span>
<span>x2=(1-5)/2=-2</span>
Ответ:
Объяснение:
|x+3|-2≠0
x+3≠2
x≠-1
x+3≠-2
x≠-5
x∈(-∞;-5)∪(-5;-1)∪(-1;+∞)