Question

Комбинаторика:

Answer 1

$\frac{4!}{1!(4-1)!} * \frac{48!}{9!(48-9)!}= \frac{4!}{3!} } * \frac{48!}{9!*39!} =4* \frac{40*41*42*43*44*45*46*47*48}{2*3*4*5*6*7*8*9} =\\=4*40*41*43*11*46*47=6708426560$