1) log(2)4096 = 12 бит = 12/8 байт = 1,5 байт
2) 1536*1024*36 бит = 1536*1024*36/(8*1024*1024) Мбайт = 6,75 Мбайт
3) 4*8*300*300*16 бит = 4*8*300*300*16 / (8*1024) Кбайт = 5625 Кбайт
4) log(2)65536 = 16 бит = 2 байта; 256*256*2 байт = 256*256*2/1024 Кбайт = 128 Кбайт
5) 2^4 = 16
1.
var a:array [1..4, 1..4] of integer; i, j, max: integer;
Begin
for i := 1 to 4 do
begin
for j := 1 to 4 do
read(a[i][j]);
readln;
end;
max := a[1][1];
for i := 2 to 4 do
if max < a[i][i] then max := a[i][i];
writeln(max);
End.
2.
var a:array [1..5, 1..5] of integer; i, j, m, sum: integer;
Begin
for i := 1 to 5 do
begin
for j := 1 to 5 do
read(a[i][j]);
readln;
end;
readln(m);
sum := 0;
for i := 1 to 5 do
if (m - i > 0) and (m - i < 6) then
sum := sum + a[i][m - i];
writeln(sum);
End.
3.
Const N = 5;
var a:array [1..N, 1..N] of integer; i, j, max: integer;
Begin
for i := 1 to N do
begin
for j := 1 to N do
read(a[i][j]);
readln;
end;
max := a[1][N];
for i := 2 to N do
if (max < a[i][N + 1 - i]) then
max := a[i][N + 1 - i];
writeln(max);
End.
4.
Const N = 5;
var a:array [1..N, 1..N] of integer; i, j, count: integer; sum: real;
Begin
for i := 1 to N do
begin
for j := 1 to N do
read(a[i][j]);
readln;
end;
sum := 0;
count := 0;
for i := 1 to N do
if (a[5][i] mod 2 = 1) then
begin
sum := sum + a[5][i];
inc(count);
end;
sum := sum / count;
writeln(sum);
End.
5.
var a:array [1..4, 1..4] of integer; i, j, upper_sum, lower_sum: integer;
Begin
for i := 1 to 4 do
begin
for j := 1 to 4 do
read(a[i][j]);
readln;
end;
upper_sum := 0;
lower_sum := 0;
for i := 1 to 4 do
begin
for j := i + 1 to 4 do
upper_sum := upper_sum + a[i][j];
for j := 1 to i - 1 do
lower_sum := lower_sum + a[i][j];
end;
writeln(upper_sum);
writeln(lower_sum);
End.