Question

Решите пожалуйстаа -x^2+2x+3=2

Answer 1

$-x^2+2x+3=2 \\-x^2+2x+3-2=0 \\-x^2+2x+1=0 \\x^2-2x-1=0 \\D=4+4=8=(2\sqrt{2})^2 \\x_1= \frac{2+2\sqrt{2}}{2} =1+\sqrt{2} \\x_2= \frac{2-2\sqrt{2}}{2} =1-\sqrt{2}$