<span>Li2CO3+H2SO4=H2O+CO2+Li2SO4</span>
<span>BACO3+H2SO4=H2O+CO2+BASO4</span>
<span>n(BaSO4)= 11,65/233=0,05</span>
<span>n(CO2) по второму уравнению = 0,05</span>
<span>n (CO2) общ = 4,48/22,4=0,2</span>
<span>n(CO2) по первому =0,2-0,05=0,15</span>
<span>n BaCO3=0,05 m=0,05*197=9,85грамм</span>
<span>n Li2CO3=0,15 m=0,15*74=11,1</span>
<span>wLi2CO3=11,1/(11,1+9,85) *100\%= 52,89\%</span>