1)14 полюбому
5SO2 + 2KMnO4 + 2H2O → 2H2SO4 + K2SO4 + 2MnSO4
ЯяяяяяяяЯяяяяяяяяяяяяяяяяЯ
А) C + K2Cr2O7 + H2SO4 -> CO2 + Cr2(SO4)3 + K2SO4 + H2O
<span><span>3 <span>C0</span></span> + <span>2 <span>K2Cr2VIO7</span></span> + <span>8 <span>H2SO4</span></span> → <span>3 <span>CIVO2</span></span> + <span>2 <span>Cr2III<span>(SO4)</span>3</span></span> + <span>2 <span>K2SO4</span></span> + <span>8 <span>H2<span>O
</span></span></span></span><span>C0</span> - <span>4e-</span> → <span>C<span>IV
</span></span><span>CrVI</span> + <span>3e-</span> → <span>Cr<span>III</span></span>
С - правильный вариант
точно не B и не D с А
Кальцій оксид, <span>Оксид серы(IV).</span>