Дано:
NaOH
-----------
W(Na) - ?
W(O) - ?
W(H) - ?
-------------
Решение:
W =
Mr(NaOH) = 23+16+1=40
W(Na) =
* 100% = 57,5%
W(O) =![\frac{16}{40} [/tex<span>] * 100% = 40% W(H) = </span>[tex] \frac{1}{40} [/tex<span>] * 100% = 2,5% </span>--------------------------- Ответ: W(Na) = 57,5% W(O) = 40% W(H) = <span>2,5% </span> Дано: К2Со ------------- W(K) - ? W(Co) - ? --------------------- Решение ----------------- W = [tex] \frac{Ar * n}{Mr}](https://tex.z-dn.net/?f=+%5Cfrac%7B16%7D%7B40%7D+%5B%2Ftex%3Cspan%3E%5D+%2A+100%25+%3D+40%25+W%28H%29+%3D%C2%A0%3C%2Fspan%3E%5Btex%5D+%5Cfrac%7B1%7D%7B40%7D+%5B%2Ftex%3Cspan%3E%5D+%2A+100%25+%3D+2%2C5%25+%3C%2Fspan%3E---------------------------+%D0%9E%D1%82%D0%B2%D0%B5%D1%82%3A%C2%A0+W%28Na%29+%3D%C2%A057%2C5%25+W%28O%29+%3D%C2%A040%25+W%28H%29+%3D%C2%A0%3Cspan%3E2%2C5%25+%3C%2Fspan%3E+%D0%94%D0%B0%D0%BD%D0%BE%3A+%D0%9A2%D0%A1%D0%BE+-------------+W%28K%29+-+%3F+W%28Co%29+-+%3F+---------------------+%D0%A0%D0%B5%D1%88%D0%B5%D0%BD%D0%B8%D0%B5+-----------------+W+%3D%C2%A0%5Btex%5D+%5Cfrac%7BAr+%2A+n%7D%7BMr%7D+)
Mr(К2Со) = 39*2+59 = 137
W(К) =
* 100% = 57%
W(Со) = [tex] \frac{59}{137} [/tex<span>] * 100% = 43%
</span>---------------------------
Ответ:
W(К) = 57%
W(Со) = 43%
NaOH
-----------
W(Na) - ?
W(O) - ?
W(H) - ?
-------------
Решение:
W =
Mr(NaOH) = 23+16+1=40
W(Na) =
W(O) =
Mr(К2Со) = 39*2+59 = 137
W(К) =
W(Со) = [tex] \frac{59}{137} [/tex<span>] * 100% = 43%
</span>---------------------------
Ответ:
W(К) = 57%
W(Со) = 43%