X(3x²+2x+1)/[(2x-7)(2x+7)]≥0
3x²+2x+1=0
D=4-12=-8<0 ⇒x∈R
x=0
2x-7=0⇒x=3,5
2x+7=0⇒x=-2,5
_ + _ +
------------(-3,5)----------[0]-------------------(3,5)--------------
x∈(-3,5;0] U (3,5;∞)
Х-1 число
у-2 число
х+15=у| >
у=4х | > х+15=4х => 3х=15, х=5
у=4*5=20
5^x * (1+5+25) = 3^x * (10+3+18)
5^x * 31 = 3^x * 31
5^x = 3^x
5^x/3^x = 1
(5/3)^x = (5/3)^0
x = 0
47y-18y=790-36 29y=754 y=754^29 y=26
10518+(1845*267+62238*(39832-39326))*41=1.151099е10