Question

Упростить выражение д) (9n+27)/(3n^2-n^3 )+((3n+9)/(n-3))^2∙(1/(3n-9)+2/(9-n^2 )-1/(n^2+3n))

Answer 1

(9n+27)/(3n^2-n^3 )+((3n+9)/(n-3))^2∙(1/(3n-9)+2/(9-n^2 )-1/(n^2+3n)) = $\frac{3*(n+3)}{ n^{2} }$ (или $\frac{9}{ n^{2} }$ + $\frac{3}{n}$)