Question

Высшая математика, комплексные числа

Answer 1

F(z1)= (1+2i)^2-(1-2i)/(1+3i)=(1-4+4i-1+2i)/(1+3i)=(-4+6i)*(1-3i)/((1+3i)*(1-3i))=(-4+6i+12i+18)/(1+9)=(14+18i)/10=1.4+1.8i
Re=1.4 Im=1.8