3nh4no3 + 2al = al2o3 + 3n2 + 6h2o
al(0) -3e = al(3+) | 3 | | 3 | 2
n(5+) +5e = n(0) | 5 | у азота будет 2 (5е-3е) | 2 | 3
n(3-) -3e = n(0) | 3 |
во первых...мышьяк однозначно лишний
1. 2СН4 -> C2H2 + 3H2
2. С2H2 + H2O -> CH3-CHO
3. CH3-CHO + H2 -> CH3-CH2-OH
4. CH3-CH2-OH + HBr -> CH3-CH2-Br + H2O
5. CH3-CH2-Br + NaOH -> CH3-CH2-OH + NaBr
6. CH3-CH2-OH + CuO -> CH3-CHO + Cu + H2O
7. CH3- CHO + Ag2O -> CH3- COOH + 2Ag
8. CH3-COOH + NaOH -> CH3-COONa + H2O
Общий объем = 8 л + 12 л = 20 л
φ(О2) = 8 л/20 л*100% = 40%
Ответ: 40%