Должно быть так? Чуток помощи =)
Sin 6x = cos 4x
sin 6x - cos 4x = 0
cos (π/2 - 6x) - cos 4x = 0
-2 sin ((π/2 - 6x+ 4x)/2) * sin ((<span>π/2 - 6x - 4x)/2) = 0
-2 sin (</span>π/4 - x) * sin (π/4 - 5x) = 0
sin (π/4 - x) = 0 | sin(π/4 - 5x) = 0
π/4 - x = πk | π/4 - 5x = <span>πk
</span>x = π/4 - πk | x = π/20 - <span>πk/5
k </span>∈ Z<span>
Ответ: </span>x = π/4 - πk , x = π/20 - <span>πk/5 , k </span><span>∈ Z</span>
13-6=7
5+6=11
7*7*7=343
11*11=121
343>121 на 222
1)100-60=40
2)60-40=20
3)120/20=6
4)60*6=360
5)40*6=240