3....................................................
Fe2O3+3H2=2Fe+3H2O
n(кол-во вещества)= 280:(56×2)=2,5 моль
n=V:Va
2,5=V:22,4
V=56 л
2Zn+O2=2ZnO
ZnO+2HNO3=Zn(NO3)2+H2O
Zn(NO3)2+2NaOH=Zn(OH)2 + 2NaNO3
Дано:
<span>w
(C) = 10,1\%
</span><span>w
(Cl) = 89,9\%</span>
<span>Mr (в-ва) =
237</span>
<span>Найти: CxCly</span>
Решение:
<span>n
(э) = w(э) ∙ Mr(в-ва) \Ar(э) ∙ 100\%</span>
<span>n
(C) = 10,1\% ∙ 237 \12 ∙ 100\% = 1,9 ≈ 2</span>
<span>n
(Cl) = 89,9\% ∙ 237\35,5 ∙ 100\% = 6</span>
<span>n (C) : n
(Cl) = 2:6 = CxCly = C2Cl6</span>
<span>ответ: C2Cl6</span>